n^2+49n-660=0

Solution for n^2+49n-660=0 equation:

n^2+49n-660=0

a = 1; b = 49; c = -660;
Δ = b2-4ac
Δ = 492-4·1·(-660)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-71}{2*1}=\frac{-120}{2}
=-60
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+71}{2*1}=\frac{22}{2}
=11
$